Gravitation MCQs | STS IBA FPSC BPSC SPSC PPSC Mcqs Test Preparation
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The gravitational force between two objects is given by which of the following formulas?
A. F = G(m₁m₂)/r²
B. F = G(m₁m₂)/r
C. F = Gm₁m₂r²
D. F = Gm₁m₂/r
Answer: F = G(m₁m₂)/r²
The gravitational potential energy of an object at height h above the Earth’s surface is given by:
A. mgh
B. Gm₁m₂ / r
C. 1/2 mv²
D. Fh
Answer: mgh
The escape velocity from a celestial body depends on:
A. The mass and radius of the body
B. The body's density and temperature
C. The body's temperature and pressure
D. The body's mass and surface area
Answer: The mass and radius of the body
The escape velocity from Earth’s surface is approximately:
A. 11.2 km/s
B. 7.9 km/s
C. 5.0 km/s
D. 12.3 km/s
Answer: 11.2 km/s
The gravitational constant G is used to calculate the:
A. Gravitational force between two objects
B. Electrical force between charges
C. Speed of light
D. Magnetic force between poles
Answer: Gravitational force between two objects
The escape velocity of an object from Earth’s surface is approximately:
A. 11.2 km/s
B. 7.9 km/s
C. 5.0 km/s
D. 12.3 km/s
Answer: 11.2 km/s
The gravitational field strength at a distance r from the center of a planet is given by:
A. GM / r²
B. GM / r
C. GM / r³
D. GM / r
Answer: GM / r²
The gravitational field strength at a height h above Earth’s surface is given by:
A. g / (1 + h/R)²
B. g / (1 – h/R)²
C. g * (1 + h/R)
D. g * (1 – h/R)
Answer: g / (1 + h/R)²
The escape velocity from Earth is approximately:
A. 11.2 km/s
B. 7.9 km/s
C. 5.0 km/s
D. 12.3 km/s
Answer: 11.2 km/s