Kinematics MCQs | STS IBA FPSC BPSC SPSC PPSC Mcqs Test Preparation
Kinematics with Targeted Online Physics Exams
Elevate your understanding of Kinematics with specialized online physics exams designed to boost your preparation. These resources provide a thorough review of basic physics concepts related to motion, velocity, and acceleration. Engage with practice tests and MCQ answers to strengthen your grasp of kinematic equations and principles. Focusing on MDCAT MCQs and other relevant practice questions can significantly enhance your performance.
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A particle starts from rest and accelerates at 3 m/s² for 4 seconds. What is the distance covered?
A. 24 meters
B. 36 meters
C. 12 meters
D. 48 meters
Answer: 24 meters
An object accelerates uniformly from 15 m/s to 35 m/s in 10 seconds. What is the acceleration?
A. 2 m/s²
B. 1.5 m/s²
C. 3 m/s²
D. 2.5 m/s²
Answer: 2 m/s²
The distance covered by an object in uniformly accelerated motion is given by which equation?
A. s = ut + (1/2)at²
B. s = ut
C. s = (1/2)at²
D. s = vt
Answer: s = ut + (1/2)at²
If an object accelerates from 10 m/s to 30 m/s in 5 seconds, what is the average acceleration?
A. 4 m/s²
B. 5 m/s²
C. 6 m/s²
D. 3 m/s²
Answer: 4 m/s²
A ball is thrown upwards with an initial speed of 20 m/s. How long does it take to reach its highest point? (Assume g = 10 m/s²)
A. 2 seconds
B. 4 seconds
C. 1 second
D. 3 seconds
Answer: 2 seconds
A car moving at 25 m/s comes to a stop in 5 seconds. What is the distance covered during this time?
A. 62.5 meters
B. 50 meters
C. 75 meters
D. 80 meters
Answer: 62.5 meters
An object in free fall from a height of 80 meters will have a velocity of:
A. 40 m/s
B. 30 m/s
C. 20 m/s
D. 25 m/s
Answer: 40 m/s
The slope of a velocity-time graph represents the:
A. Acceleration
B. Speed
C. Distance
D. Displacement
Answer: Acceleration
The time taken for an object to reach its maximum height when thrown vertically is:
A. Initial velocity divided by acceleration due to gravity
B. Total time of flight divided by 2
C. Initial velocity divided by 2g
D. Initial velocity divided by gravity
Answer: Initial velocity divided by gravity